Overview of PT100 sensor chip:
When PT100 is at 0 degrees Celsius, its resistance is 100 ohms, which is why it is named PT100. Its resistance will increase at an approximately uniform rate as the temperature rises. But the relationship between them is not a simple proportional relationship, but should be closer to a parabola. Since the isolation of PT100 resistance per degree Celsius is very small, within 1Ω, it is destined to have a more complicated circuit, because in actual use, the wire will be longer, there will be line resistance, and there will be interference, so it is more troublesome to read the resistance. PT100 usually has two-wire, three-wire and four-wire measurement methods, each with its own advantages and disadvantages. The more wires, the more complex the measurement circuit and the higher the cost, but the corresponding accuracy is better. There are usually several test schemes, using a dedicated IC for reading, or a constant current source, or an op amp to build. Dedicated ICs are naturally expensive, so this article uses an op amp to build and collect PT100 resistance values. The following figure is a partial picture of the PT100 scale:
Pt100 chip, that is, its resistance is 100 ohms at 0 degrees, 18.52 ohms at -200 degrees, 175.86 ohms at 200 degrees, En 375.70 ohms at 800 degrees.
The thermal resistance formula is in the form of Rt=Ro(1+A*t+B*t*t);Rt=Ro[1+A*t+B*t*t+C(t-100)*t*t*t], t represents Celsius temperature, Ro is the resistance value at zero degrees Celsius, A, B, C are all specified coefficients, for Pt100, Ro is equal to 100℃.
The measurement range of Pt100 temperature sensor:
-200℃~+850℃; allowable deviation value △℃: Class A ±(0.15+0.002│t│), Class B ±(0.30+0.005│t│). Thermal response time <30S; minimum insertion depth: the minimum insertion depth of the thermal resistor is ≥200mm.
Allowable current ≤5mA. In addition, the Pt100 temperature sensor also has the advantages of vibration resistance, good stability, high accuracy, and high voltage resistance.
See? The current cannot be greater than 5mA, and the resistance changes with temperature, so the voltage should also be paid attention to.
In order to improve the accuracy of temperature measurement, a 1V bridge power supply should be used, and the 5V reference power supply of the A/D converter should be stable at the 1mV level. If the price allows, the linearity of the Pt100 sensor, A/D converter and op amp should be high. At the same time, using software to correct its error can make the measured temperature accurate to ±0.2℃.
The use of Pt100 temperature sensor, Pt100 temperature sensor is an analog signal. It has two forms in practical applications: one is that it does not need to be displayed and is mainly collected to plc. In this case, when using it, only one pt100 integrated circuit is needed. It should be noted that this integrated circuit collects not current signals but resistance values. The pt100 integrated circuit (needs a +-12VDC power supply to provide working voltage) directly converts the collected resistance into 1-5VDC and inputs it into the plc. After a simple +-*/ calculation, the corresponding temperature value can be obtained (this form can collect multiple channels at the same time). Another type is a single pt100 temperature sensor (working power supply is 24VDC), which generates a 4-20MA current, and then converts the 4-20MA current into 1-5V voltage through a 4-20MA current circuit board. The difference is that it can be connected to an electromagnetic indicating instrument. The rest is basically the same, so I won’t explain it in detail.
Application range
* Bearings, cylinders, oil pipes, water pipes, steam pipes, textile machines, airconditioners, water heaters and other small space industrial equipment temperature measurement and control.
* Car air conditioners, koelkasten, freezers, water dispensers, coffee machines, dryers, medium and low temperature drying ovens, constant temperature boxes, enz.
* Heating/cooling pipeline heat metering, central air conditioning household heat energy metering and industrial field temperature measurement and control.
Overview of the principle of three-wire PT100
The figure above is a three-wire PT100 preamplifier circuit. The PT100 sensor leads to three wires of exactly the same material, wire diameter and length, and the connection method is shown in the figure. A 2V voltage is applied to the bridge circuit composed of R14, R20, R15, Z1, PT100 and its wire resistance. Z1, Z2, Z3, D11, D12, D83 and each capacitor play a filtering and protection role in the circuit. They can be ignored during static analysis. Z1, Z2, Z3 can be regarded as short circuit, and D11, D12, D83 and each capacitor can be regarded as open circuit. From the resistor voltage divider, V3=2*R20/(R14+20)=200/1100=2/11 ……a. From the virtual short, the voltage of pins 6 En 7 of U8B is equal to the voltage of pin 5 V4=V3 ……b. From the virtual short circuit, we know that no current flows through the second pin of U8A, so the current flowing through R18 and R19 is equal. (V2-V4)/R19=(V5-V2)/R18 ……c. From the virtual short circuit, we know that no current flows through the third pin of U8A, V1=V7 ……d. In the bridge circuit, R15 is connected in series with Z1, PT100 and line resistance, and the voltage obtained by connecting PT100 and line resistance in series is added to the third pin of U8A through resistor R17, V7=2*(Rx+2R0)/(R15+Rx+2R0) ……e. From the virtual short circuit, we know that the voltage of the third pin and the second pin of U8A are equal, V1=V2 ……f. From abcdef, we get (V5-V7)/100=(V7-V3)/2.2. Simplified, we get V5=(102.2*V7-100V3)/2.2, that is, V5=(204.4(Rx+2R0)/(1000+Rx+2R0) – 200/11)/2.2 ……g. The output voltage V5 in the above formula is a function of Rx. Let’s look at the influence of line resistance. Note that there are two V5s in the circuit diagram. In the context, we refer to the one on U8A. There is no relationship between the two. The voltage drop generated on the line resistance at the bottom of PT100 passes through the middle line resistance, Z2, and R22, and is added to the 10th pin of U8C. From the virtual disconnection, we know that V5=V8=V9=2*R0/(R15+Rx+2R0) ……a. (V6-V10)/R25=V10/R26……b. From the imaginary short circuit, we know that V10=V5……c. From the formula abc, we get V6=(102.2/2.2)V5=204.4R0/[2.2(1000+Rx+2R0)]……H. From the equation group composed of formula gh, we know that if the values of V5 and V6 are measured, Rx and R0 can be calculated. Knowing Rx, we can know the temperature by looking up the PT100 scale. Daarom, we get two formulas, namely V6=204.4R0/[2.2(1000+Rx+2R0)] and V5=(204.4(Rx+2R0)/(1000+Rx+2R0) – 200/11)/2.2. V5 and V6 are the voltages we want to collect, which are known conditions. To get the final formula, we have to solve these two formulas. By the way, Z1, Z2 and Z3 are three three-terminal filter through-hole capacitors. The actual objects are shown in the figure below, with plug-in and surface mount versions.